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26-02-2021
Chemistry

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At room temperature and pressure 14.2 g of chlorine will occupy what volume of gas

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26-02-2021

Answer:

9.6[tex]dm^{3}[/tex]

Explanation:

Volume at room temperature & pressure = no. of moles × 24[tex]dm^{3}[/tex]

No. of moles = mass ÷ mass of 1 mole

= 14.2 ÷ 35.5

= 0.4 moles

Volume = 0.4 × 24 = 9.6[tex]dm^{3}[/tex]

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