jude28 jude28
  • 26-02-2021
  • Mathematics
contestada

Find AC!
Round to the nearest tenth.
B.
239
132
6
A

Find AC Round to the nearest tenth B 239 132 6 A class=

Respuesta :

akposevictor
akposevictor akposevictor
  • 03-03-2021

Answer:

11.4

Step-by-step explanation:

Given:

B = 132°

C = 23°

c = AB = 6

Required:

AC (b)

Solution:

Apply the Law of Sines

[tex] \frac{b}{sin(B)} = \frac{c}{sin(C)} [/tex]

Plug in the values

[tex] \frac{b}{sin(132)} = \frac{6}{sin(23)} [/tex]

Multiply both sides by sin 132

[tex] b = \frac{6*sin(132)}{sin(23)} [/tex]

b = 11.4116041

b = AC ≈ 11.4 (nearest tenth)

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