-(x+2)^2(x-4)^2
Not that if x= -2 and x=4 they will look like this in an equation: (x+2) and (x-4)
When (x+2) and (x-4) are set equal to zero and you solve for x, x will equal x= -2 and x=4
If they have double roots, they have a multiplicity of 2 (per root) meaning they will bounce off of the x-axis. Multiplicity can be found by using exponents.
The negative in front flips the function over the x-axis and holds true to the given limit.
