Answer:
Answer: Choice C
Step-by-step explanation:
The Magnitude of a Vector
Given a vector in the form:
[tex]\mathbf{v}=x\mathbf{i}+y\mathbf{j}[/tex]
The magnitude of the vector is:
[tex]\mid\mid \mathbf{v}\mid\mid=\sqrt{x^2+y^2}[/tex]
We are given the vector:
[tex]\mathbf{v}=17\mathbf{i}-39\mathbf{j}[/tex]
The magnitude is:
[tex]\mid\mid \mathbf{v}\mid\mid=\sqrt{17^2+(-39)^2}[/tex]
[tex]\mid\mid \mathbf{v}\mid\mid=\sqrt{289+1521}=\sqrt{1810}[/tex]
Answer: Choice C
