doudi67 doudi67
  • 23-01-2021
  • Mathematics
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For this 45-45-90 trinagle...??

For this 454590 trinagle class=

Respuesta :

manissaha129
manissaha129 manissaha129
  • 23-01-2021

Answer:

[tex] {x}^{2} + {x}^{2} = {(3 \sqrt{2} )}^{2} \\ 2 {x}^{2} = 18 \\ {x}^{2} = \frac{18}{2} \\ {x}^{2} = 9 \\ \boxed{x = 3}[/tex]

Therefore the length of the legs is 3.

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