Problem:
Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.
Solution:
[tex] - 10 - ( - 2) = \boxed{ - 8}[/tex]
[tex] - 8 - ( - 2) = \boxed{ - 6}[/tex]
[tex] - 6 - ( - 2) = \boxed{ - 4}[/tex]
[tex] - 4 - ( - 2) = \boxed{ - 2}[/tex]
[tex] - 2 - ( - 2) = \boxed{0}[/tex]
[tex]0 - ( - 2) = \boxed{2}[/tex]
[tex]2 - ( - 2) = \boxed{4}[/tex]
[tex]4 - ( - 2) = \boxed{6}[/tex]
[tex]6 - ( - 2) = \boxed{8}[/tex]
Answer:
-10, -8, -6, -4, -2, 0, 2, 4, 6, 8
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