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  • 24-12-2020
  • Mathematics
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prove that
(pSinB-rcosB)2 +(rsinB+pcosB)2=p2+r2​

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LammettHash
LammettHash LammettHash
  • 24-12-2020

Expand the binomials, then simplify, then invoke the Pythagorean identity:

(p sin(B) - r cos(B))² + (r sin(B) + p cos(B))²

= (p² sin²(B) - 2pr sin(B) cos(B) + r ² cos²(B)) + (r ² sin²(B) + 2pr sin(B) cos(B) + p² cos²(B))

= p² (sin²(B) + cos²(B)) + r ² (cos²(B) + sin²(B))

= p² + r ²

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