Given :
[tex]m_1 = 82 \ kg\\\\v_1 = 257 m/s\\\\m_2 = 60 kg[/tex]
Let, us assume that momentum is conserved during the process.
To Find :
The velocity [tex]v_2[/tex] .
Solution :
Applying conservation of momentum :
Initial momentum = Final momentum
[tex]m_1v_1 = m_2v_2\\\\82\times 257=60\times v_2\\\\v_2 = \dfrac{82\times 257}{60}\ m/s\\\\v_2 = 351.23\ m/s[/tex]
Hence, this is the required solution.
