briannabennett1214 briannabennett1214
  • 22-12-2020
  • Chemistry
contestada

What volume of 18.0 M sulfuric acid must be used to prepare 15.5 L of 0.195
M H2SO4?
none of these
0.336 L
168 mL
O 92.3 mL
226 mL

Respuesta :

arslanamir186
arslanamir186 arslanamir186
  • 22-12-2020

Answer:

168 ml

Explanation:

M1V1= M2V2

V1=M2V2/M1

V1= 0.195×15.5/18

V1 = 0.1679 L=168ml

Answer Link
okpalawalter8
okpalawalter8 okpalawalter8
  • 30-12-2021

Answer:

  • Volume needed to prepare 18.0 M sulfuric acid = [tex]168mL[/tex](Option B)

Explanation:

Given,

[tex]M_1 = 18M\\\\M_2 = 0.195\\\\V_1 = ?\\\\V_2 = 15.5[/tex]

Therefore,

[tex]M_1 * V_1 = M_2 * V_2\\\\ V_1 = \frac{M_2*V_2}{M_1}\\\\V_1 = \frac{0.195*15.5}{18}\\\\V_1 = 0.168L \\\\V_1 = 168mL[/tex]

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Answer Link

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