Let the eq of circle be
x
2
+y
2
+2gx+2βy+c=0
now, x intercept = 2
g
2
−c
But circle touches x axis ∴ x intercept = 0
∴2
g
2
−c
=0∴g
2
=c
∴eq
n
become x
2
+y
2
+3gx+2βy+g
2
=0
Now circle passes through (3, 0) and (1, 4)
∴(3)
2
+(0)
2
+2g(3)+0+g
2
=0
9+6g+g
2
=0
∴g=−3
Also (1)
2
+(4)
2
+2(−3)(1)+2β(4)+9=0
∴1+16−6+8β+9=0
∴20+8β=0 ∴β=
2
5
Hence eq
n
of circle is
x
2
+y
2
−6x−5y+9=
