solmelch0204 solmelch0204
  • 21-11-2020
  • Chemistry
contestada

how many grams of sodium hydroxide are required to dissolve in 232 g of water to make a 2.88 m solution

Respuesta :

ardni313
ardni313 ardni313
  • 24-11-2020

Grams of Sodium hydroxide : 26.72 g

Further explanation

Molality shows the number of moles dissolved in every 1000 grams of solvent.

m = n. (1000 / p)

m = Molality

n = Number of moles of solute

p = Solvent mass (gram)

Can be written :

[tex]\tt m=\dfrac{mol~solute}{kg~solvent}[/tex]

  • mol solute(NaOH)

m=2.88

kg solvent(water)=232 g=0.232 kg

[tex]\tt mol~solute=m\times kg~solvent\\\\mol~solute=2.88\times 0.232=0.668[/tex]

  • mass of NaOH

[tex]\tt mass=mol\times MW\\\\mass=0.668\times 40~g/mol=26.72~g[/tex]

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