jahlynrichard jahlynrichard
  • 24-10-2020
  • Mathematics
contestada

What is an equation of the line that passes through the point (8,2) and is parallel to the line x+4y=28

Respuesta :

devishri1977
devishri1977 devishri1977
  • 25-10-2020

Answer:

[tex]y =\frac{-1}{4}x + 4[/tex]

Step-by-step explanation:

Parallel lines have same slope

x + 4y = 28

    4y = -x + 28

     [tex]y=\frac{-1}{4}x+\frac{28}{4}\\\\y=\frac{-1}{4}x+7[/tex]

m = (-1/4) and line passes through (8 , 2)

Equation: y - y₁ = m(x - x₁)

  [tex]y - 2 = \frac{-1}{4}(x - 8)\\\\y -2 = \frac{-1}{4}x - 8*\frac{-1}{4}\\\\y -2 = \frac{-1}{4}x + 2\\\\ y = \frac{-1}{4}x + 2 +2\\\\ y =\frac{-1}{4}x + 4[/tex]

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