Answer:
The new volume is 322.55ml
Explanation:
i.e
[tex] \frac{ v_{1}}{ t_{1} } \: = \frac{ v_{2}}{ t_{2} } \\ making \: v_{2} \: the \: subject \: of \: the \\ relation, \: then \: { v_{2}} = \frac{ v_{1} \: \times \: t_{2} }{ t_{1} } [/tex]
[tex]so \: v_{2} \: = ( \frac{285 \: \times \: (62 \: + \: 273)}{(23 \: + \: 273)} ) \: = \: 322.55ml.[/tex]
note, the temperature was converted to kelvin.
