Answer:
The principal quantum number for the outermost electrons in a Cl atom in the ground state is 3.
Explanation:
By using the Pauling distribution the chlorine atom has an electronic set of [tex]3s1^{2}[/tex]
With n=3 for an orbital S, l = 0 , ml = 0 and ms = ± 1/2
Therefore the final answer is 3
