mariz4L8illika
mariz4L8illika mariz4L8illika
  • 22-09-2016
  • Mathematics
contestada

\[y^{\prime\prime} 4y=\cos2x\]

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kramermccauslan
kramermccauslan kramermccauslan
  • 29-09-2016
So the question if find y'' for 4y=cos2x

First, find y by dividing by 4.  y = cos2x/4
Then, take the first derivative.  y' = -sin2x/2
Then, take the second dervative.  y'' = -cos2x
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