teknarayanpaudel teknarayanpaudel
  • 24-05-2020
  • Mathematics
contestada

2x^2 / x^2 - y^2 - x^2 / xy - y ^ 2​

Respuesta :

jimzhu
jimzhu jimzhu
  • 24-05-2020

Answer:

2 - 2y^2 - x/y

Step-by-step explanation:

2x^2/x^2 = 2

and

x^2/xy = x/y

therefore

2x^2/x^2 - y^2 - x^2/xy - y^2

= 2 - y^2 - x/y - y^2

= 2 - y^2 - y^2 - x/y

= 2 - 2y^2 - x/y

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