homeysungh homeysungh

26-04-2020
Mathematics

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Determine the slope of the tangent to the graph of y=-x^3+2.5x^2-3x+1 at the point where x=2

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surjithayer10 surjithayer10

27-04-2020

Answer:

-5

Step-by-step explanation:

[tex]\frac{dy}{dx} =-3x^2+5x-3\\x=2\\\frac{dy}{dx} =-3(2)^2+5(2)-3=-12+10-3=-5[/tex]

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