slondono25 slondono25
  • 22-03-2020
  • Mathematics
contestada

3 ( 1 + 2b) + 2 < 71

Respuesta :

igoroleshko156
igoroleshko156 igoroleshko156
  • 22-03-2020

Answer:

b < 11

Step-by-step explanation:

Step 1:  Distribute

3(1 + 2b) + 2 < 71

(3 * 1) + (3 * 2b) + 2 < 71

3 + 6b + 2 < 71

Step 2:  Combine like terms

3 + 6b + 2 < 71

5 + 6b < 71

Step 3:  Subtract 5 from both sides

5 + 6b - 5 < 71 - 5

6b < 66

Step 4:  Divide both sides by 6

6b / 6 < 66 / 6

b < 11

Answer:  b < 11

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