Step-by-step explanation:
[tex] {x}^{2} = {2}^{2} + ( \sqrt{2 \times 6)}^{2} \\ \\ \therefore \: {x}^{2} = 4 + 12 \\ \\ \therefore \: {x}^{2} = 16 \\ \\ \huge \red{ \boxed{ x = 4}}[/tex]
