Step-by-step explanation:
Given sequence is: - 3, 5, 13...
Here first term a = - 3
common difference d= 5-(-3)=13-5=8
Hence, it is in A. P.
Nth term of an AP is given as:
[tex]t_n = a + (n - 1)d \\ \\ \therefore \: t_n = - 3 + (n - 1) \times 8 \\ \\ \therefore \: t_n = - 3 + 8n - 8 \\ \\ \huge \red{ \boxed{\therefore \: t_n = 8n - 11}}[/tex]
Which is the required formula for the given sequence.
