Answer:
x² + y² + 2y - 1 = 0
Step-by-step explanation:
The general form of the equation for the circle:
x² + y² + ax + by + c = 0
Where: a, b and c are constants.
For the given equation:
x² + (y + 1)² = 2
∴ x² + (y + 1) (y+1) = 2
∴ x² + y² + 2y + 1 = 2 ⇒ subtract 2 from both sides
∴ x² + y² + 2y + 1 - 2 = 2 - 2
∴ x² + y² + 2y - 1 = 0
So, the general form of the equation for the circle:
x² + y² + 2y - 1 = 0
