Answer: 3.75 m
Explanation:
5 squirts in 1 second
So, 1 squirt in 1/5 second which is 0.2 second.
The difference in timing of two consecutive squirt is 0.2 second, so
time (t) = 0.2 s.
speed (s) = 15 m/s
Distance of separation (d) = ?
Now, formula for distance is
d = s × t
d = 15 × 0.2
d = 3.75 m
