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24-12-2019
Advanced Placement (AP)

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In ∆ABC, m∠ACB = 90°, m∠A = 40°,

CD

(D ∈

AB

) is a segment perpendicular to side

AB

. Find m∠DBC and m∠BCD.

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24-12-2019

Answer:

u get this diagram^

to find DBC

B+40+90=180

B=50°

to find BCD

CDB is 90° ( since perpendicular to AB)

so taking triangle BCD

90+50+c=180

c=40°

Explanation:

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