Answer:
C = [tex]$ \frac{1}{10} $[/tex]
D = [tex]$ \frac{1}{10^2} $[/tex]
Step-by-step explanation:
78.09 = 7 [tex]$ \times A + 8 \times B + 0 \times C + 9 \times D $[/tex]
78.09 = 7 [tex]$ \times 10^1 + 8 \times 10^0 + 0 \times \frac{1}{10} + 9 \times \frac{1}{10^2}[/tex]
⇒ C = [tex]$ \frac{1}{10} $[/tex]
D = [tex]$ \frac{1}{10^2} $[/tex]
Hence, the answer.
