Milla57 Milla57
  • 22-11-2019
  • Mathematics
contestada

the inverse of the function f(x)=
[tex] \sqrt{x + 3} + 2[/tex]
​

Respuesta :

Yang100
Yang100 Yang100
  • 01-12-2019

Answer:

f^-1 (x)=x^2-4x+1

Step-by-step explanation:

y=sqrt(x+3)+2

x=sqrt(y+3)+2

sqrt(y+3)=x-2

y+3=(x-2)^2

y+3=(x-2)(x-2)

y+3=x^2-2x-2x+4

y+3=x^2-4x+4

y=x^2-4x+4-3

y=x^2-4x+1

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