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An 800-kHz sinusoidal radio signal is detected at a point 6.6 km from the transmitter tower. The electric field amplitude of the signal at that point is 0.780 V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the amplitude of the magnetic field of the signal at that point

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Answer:

0.0000000026 T

Explanation:

[tex]E_0[/tex] = Maximum electric field strength = 0.78 V/m

[tex]B_0[/tex] = Maximum magnetic field strength

c = Speed of light = [tex]3\times 10^8\ m/s[/tex]

Relation between amplitudes of electric and magnetic fields is given by

[tex]E_0=B_0c\\\Rightarrow B_0=\frac{E_0}{c}\\\Rightarrow B_0=\frac{0.78}{3\times 10^8}\\\Rightarrow B_0=0.0000000026\ T[/tex]

The amplitude of the magnetic field is 0.0000000026 T

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