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A point source of light is 1.24 m below the surface of a pool. What is the diameter of the circle of light that a person above the water will see? Assume the water has an index of refraction of ????=1.33.

Respuesta :

Answer:

D = 2.828 m

Explanation:

given,

distance of source of light = 1.24 m below surface of pool

refractive index of the water Ā = nā‚ = 1.33

refractive index of air = nā‚‚ = 1

refraction angle be = 90Ā°

let C be the critical angle

Radius = d tan C

d is the depth of the source

Using Snell's law

nā‚ sin C = nā‚‚ sin R

1.33 x sin C = 1 x Ā sin 90Ā°

[tex]sin C = \dfrac{1}{1.33}[/tex]

[tex]C = sin^{-1}(0.752)[/tex]

C = 48.75Ā°

hence,

R = 1.24 x tan 48.75Ā°

R = 1.414 m

Diameter = 2 x R

D = 2 x 1.414

D = 2.828 m

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