Answer:
321 m/s
Explanation:
First, find the time it takes for the bullet to hit the ground.
Given (in the y direction):
Δy = 1.90 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(1.90 m) = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.623 s
Next, find the horizontal velocity needed to travel 200.0 m in that time.
Given (in the x direction):
Δx = 200.0 m
t = 0.623 s
a = 0 m/s²
Find: v₀
Δx = v₀ t + ½ at²
(200.0 m) = v₀ (0.623 s) + ½ (0 m/s²) (0.623 s)²
v₀ = 321 m/s
