Respuesta :

[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=6 \end{cases}\implies 6=\pi r^2\implies \cfrac{6}{\pi }=r^2 \\\\\\ \sqrt{\cfrac{6}{\pi }}=r\implies 1.38\approx r[/tex]

Otras preguntas