Answer:
Step-by-step explanation:
Given a quadratic equation
ax^2+bx+c=0
you can find its solutions with the following formula:
x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}
You equation is identified by the coefficients
x^2 - 3x + 5 \iff a = 1,\ b = -3,\ c = 5
Which means the solutions are
\dfrac{3 \pm \sqrt{9-4\cdot 5}}{2} = \dfrac{3 \pm \sqrt{-11}}{2}
