jaylo2x32
jaylo2x32 jaylo2x32
  • 25-09-2019
  • Mathematics
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Write V64 - V-289 as a complex number in the form of a + bi.
A. 8-171
B. 8 + 171
C. 17+ 8i
D.-17-81
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freckledspots freckledspots
  • 25-09-2019

Answer:

8-17i

The problem:

[tex]\sqrt{64}-\sqrt{-289}[/tex]

Step-by-step explanation:

[tex]\sqrt{64}=8[/tex] because 8 is positive and 8(8)=64.

[tex]\sqrt{-289}=17i[/tex] because 17i(17i)=289i^2=289(-1)=-289[/tex]

[tex]\sqrt{64}-\sqrt{-289}[/tex]

[tex]8-17i[/tex]

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