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22-08-2019
Mathematics

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Rewrite the square root of 36 as a product of two square roots of perfect squares.

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jdoe0001 jdoe0001

22-08-2019

[tex]\bf \begin{cases} 3^2=9\\ 2^2=4 \end{cases}\qquad \qquad \sqrt{9}\cdot \sqrt{4}\implies \sqrt{9\cdot 4}\implies \sqrt{36}[/tex]

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