[tex]\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &2250\\ r=rate\to 35\%\to \frac{35}{100}\dotfill &0.35\\ t=\textit{elapsed time}\dotfill &3\\ \end{cases} \\\\\\ A=2250(1-0.35)^3\implies A=2250(0.65)^3\implies A\approx 617.91[/tex]
