lala91101
lala91101 lala91101
  • 23-04-2016
  • Mathematics
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how do i solve 4m^2+3m-1=0 using the quadratic formula

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apologiabiology
apologiabiology apologiabiology
  • 23-04-2016
quadratic formulat is used when a^2+bx+c=0 x= [tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex] 4m^2+3m-1=0 a=4 b=3 c=-1 input x= [tex] \frac{-3+/- \sqrt{3^{2}-4(4)(-1)} }{2(4)} [/tex] x= [tex] \frac{-3+/- \sqrt{9+16} }{8} [/tex] x= [tex] \frac{-3+/- \sqrt{25} }{8} [/tex] x= [tex] \frac{-3+/-5 }{8} [/tex] x= [tex] \frac{-8}{8} [/tex] or [tex] \frac{2}{8} [/tex] x=-1 or 1/4
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