mambas2001 mambas2001
  • 26-01-2019
  • Mathematics
contestada

In ΔABC, m∠ACB = 90°, and m∠ACD = 45°.
Find CD, if BC = 3in.

In ΔABC mACB 90 and mACD 45 Find CD if BC 3in class=

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Karishma77
Karishma77 Karishma77
  • 26-01-2019

Answer:


Step-by-step explanation:

We need to find CD

since ANGLE ACD=45

ANGLE BCD=45

COS 45=CD/CB

1/2=CD/3

so CD =3/2

Mark as brainiest

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abidemiokin
abidemiokin abidemiokin
  • 20-04-2020

Answer:

3/√2 inches

Step-by-step explanation:

From the ∆ACB,

∠ACD + ∠DCB = 90°

45° + ∠DCB = 90°

∠DCB = 90° - 45°

∠DCB = 45°

Using sine rule on ∆CDB to get BC,

BC/∠CDB = CD/∠CBD

BC/sin90° = CD/sin45°

3/sin90° = CD/sin45°

3 = CD/(1/√2)

3 = √2 × CD

CD = 3/√2 inches

Answer Link

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