[tex]3\frac{5}{8} = \frac{29}{8}[/tex]
[tex]\frac{1}{3}(3\frac{5}{8} )=(\frac{1}{3} (\frac{24}{8} ))+(\frac{1}{3} (\frac{5}{8} ))[/tex]
[If you can't type fractions, then instead of 24/8, do 3]
The first missing value is 3 or [tex]\frac{24}{8}[/tex]
= [tex]\frac{3}{3} + \frac{5}{24}[/tex]
The second missing value is 24 (because 3 times 8 is 24)
= [tex]\frac{24}{24}+ \frac{5}{24}[/tex] Make the denominators the same in order to add them together
= [tex]\frac{29}{24}[/tex]
The third missing value is 29
