Answer : A
We need to simplify the given expression
Lets factor numerator first
[tex]2x^2-5x-3[/tex] =(2x+1)(x-3)
[tex]x^2+8x+15[/tex] =(x+5)(x+3)
Now we factor the denominator
[tex]x^2+x-20[/tex] =(x+5)(x-4)
[tex]2x^2+9x+4[/tex] =(2x+1)(x-4)
Now we simplify it
[tex]\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}[/tex]
Now cancel out same factors. so we left with
[tex]\frac{(x+3)(x-3)}{(x+4)(x-4)} }[/tex]
Now multiply the factors
[tex]\frac{x^2-9}{x^2-16} }[/tex]
