joshualbrown730 joshualbrown730

24-10-2018
Physics

contestada

A spring with a constant of 350.N/m is stretched to store 210.J of energy. How much has the spring been stretched?

Respuesta :

Sebastian11118 Sebastian11118

24-10-2018

The formula for the potential energy of a spring is U = (1/2)kx^2. So you set U equal to 200 J, k equal to 1000 N/m, and solve for x.

Rearranging, the equation you have to solve is x = (2U/k)^(1/2). So you'll get that x has to be equal to 0.632 m.

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