Respuesta :

Pyth. theorem
[tex] \sqrt{20 { }^{2} - 8 {}^{2} } [/tex]

=18.33
=18.3 (corr. to the nearest tenth)
remotecontrolbrain

Use Pythagorean theorem.

Let x be the side we are looking to determine:

[tex]x = \sqrt{20^2-8^2}=\sqrt{336}\approx 18.3[/tex]

the missing measure is approximately 18.3 units


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