countryreflectp8advo countryreflectp8advo
  • 22-09-2018
  • Physics
contestada

What are the components of vector B if it’s magnitude is 18 m and makes an angle of 112 degrees with the +x- axis?

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Blacklash
Blacklash Blacklash
  • 22-09-2018

Any vector can be written as components along positive X and positive Y axes.

So vector B can be written as [tex]Bcos(\theta)i+Bsin(\theta)j[/tex], where [tex]\theta[/tex] is the angle between vector and positive X axis

So vector B = [tex]18*cos(112)i+18*sin(112)j=-6.74i+16.69j[/tex]

So components of vector B along X -axis =-6.74 m

                                              along Y-axis = 16.69 m

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