22-08-2018
Mathematics

contestada

Simplify:
2x(with a 3 exponent) y(with a 3 exponent) over 4y(with a 2 exponent)

Respuesta :

22-08-2018

[tex] \frac{2x^{3}y^{3}}{4y^{2}} \newline \textrm{Take away exponents on y terms} \newline \frac{2x^{3}y}{4} \newline\textrm{Simplify} \newline \frac{x^{3}y}{2} [/tex]

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