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AnthrαX
Hey Luckycharms1233, 

Lets find the product of your equation together, 

          Lets simplify this step by step, shall we. 

We want to find the [tex]derivative\:of\:F\left(x\right)=-x^2-x+2[/tex]. 

[tex]\dfrac{d}{dx}\left(-x^2-x+2\right)[/tex] 

Now we have to [tex]\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)^'=f^'\pm g^'[/tex]. 

This leads to : [tex]-\frac{d}{dx}\left(x^2\right)-\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(2\right)[/tex]. 

        Now we simplify. 

[tex]\dfrac{d}{dx}\left(x^2\right)=2x[/tex] 

[tex]\dfrac{d}{dx}\left(x\right)=1[/tex] 

[tex]\dfrac{d}{dx}\left(2\right)=0[/tex] 

     Finally we arrive at : [tex]-2x-1+0[/tex] 

This can be simplified to [tex]-2x-1[/tex] 

          Our graph should look like the one below 

Hope this helps, 

        AnthrαX
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