gusperez21 gusperez21
  • 25-02-2016
  • Chemistry
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how many L of a .05 M HCL solution can be made by diluting 250 ml of 10 M HCL

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Willchemistry
Willchemistry Willchemistry
  • 25-02-2016
Mi  * Vi = Mf * Vf

10 * 0.25 = 0.05 * Vf

2.5 = 0.05* Vf

Vf = 2.5 / 0.05

Vf = 50 L

hope this helps!



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