Respuesta :
Radius of the circle: r
Area of the circle: A1=pi r^2
A1=3.141592654 r^2
Area of the regular hexagon: A2=(6)(1/2)(r)(r) sin 60°
A2=(6/2) r^2 sqrt(3)/2
A2=3 sqrt(3) r^2 /2
A2=3(1.732050808) r^2/2
A2=2.598076212 r^2
a. What percent of the area of the circle is overlapped by the area of the inscribed regular hexagon?
Percentage: P=(A2/A1)*100%
P=[2.598076212 r^2 / (3.141592654 r^2)]*100%
P=(0.826993343)*100%
P=82.6993343%
P=82.7%
Answer: 82.7 percent of the area of the circle is overlapped by the area of the inscribed regular hexagon.
b. if the radius of the circle is tripled and a regular hexagon is inscribed in the new circle, what percent of the area of the circle is overlapped by the area of the inscribed regular hexagon?
The same percentage.
Answer: 82.7 percent of the area of the circle is overlapped by the area of the inscribed regular hexagon.
Area of the circle: A1=pi r^2
A1=3.141592654 r^2
Area of the regular hexagon: A2=(6)(1/2)(r)(r) sin 60°
A2=(6/2) r^2 sqrt(3)/2
A2=3 sqrt(3) r^2 /2
A2=3(1.732050808) r^2/2
A2=2.598076212 r^2
a. What percent of the area of the circle is overlapped by the area of the inscribed regular hexagon?
Percentage: P=(A2/A1)*100%
P=[2.598076212 r^2 / (3.141592654 r^2)]*100%
P=(0.826993343)*100%
P=82.6993343%
P=82.7%
Answer: 82.7 percent of the area of the circle is overlapped by the area of the inscribed regular hexagon.
b. if the radius of the circle is tripled and a regular hexagon is inscribed in the new circle, what percent of the area of the circle is overlapped by the area of the inscribed regular hexagon?
The same percentage.
Answer: 82.7 percent of the area of the circle is overlapped by the area of the inscribed regular hexagon.
