Respuesta :

apologiabiology
so first find the slope of the bondary line

y=mx+b
m=sloe
b=y intercept
seems to have a y intercept at y=-3

b=-3

y=mx-3

another point is (6,0)
input that, remember (x,y)
x=6, y=0 is a point
0=m(6)-3
0=6m-3
3=6m
1/2=m


equation of boundary line is y=1/2x-3
dahsed line so it is >  or <
see if it is which one

test y<1/2x-3
find a point in the shaded area and see if it is true
(6,-3)
-3<1/2(6)-3
-3<3-3
-3<0
true
the equation is y<(1/2)x-3

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