gtsaeg9716 gtsaeg9716 25-05-2023 Mathematics contestada (ii).If X₁ (t) = e¹tU₁₂,X₂(t) = e^t (U₂ + tU)... X₁ (t) = e¹t (U₁ + tU₁ k-1+...+u2tk-1/ (k-1)!) Are solutions of X' = AX, then X1....Xk are linearly independent,i.e. C₁X₂ + C₂X₂ + + CX = 0 for some arbitrary constants C, s. [4 marks]
