For this case we have:
Let a function of the form [tex]y = f (x)[/tex]
By definition, to graph [tex]y = f (x + h)[/tex], where [tex]h> 0[/tex], we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that [tex]h = 3[/tex]
So, if the black graph is given by[tex]y = f (x)[/tex], the red graph is given by: [tex]y = f (x + 3)[/tex]
Answer:
[tex]y = f (x + 3)[/tex]
Option A
